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(2/5)m=(17/4)
We move all terms to the left:
(2/5)m-((17/4))=0
Domain of the equation: 5)m!=0We add all the numbers together, and all the variables
m!=0/1
m!=0
m∈R
(+2/5)m-((+17/4))=0
We multiply parentheses
2m^2-((+17/4))=0
We multiply all the terms by the denominator
2m^2*4))-((+17=0
Wy multiply elements
8m^3+17=0
We do not support empression: m^3
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