(2/5)n+(1/10)=0.5(n+4)

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Solution for (2/5)n+(1/10)=0.5(n+4) equation: 



(2/5)n+(1/10)=0.5(n+4)

We move all terms to the left:

(2/5)n+(1/10)-(0.5(n+4))=0



Domain of the equation: 5)n!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

(+2/5)n-(0.5(n+4))+(+1/10)=0

We multiply parentheses

2n^2-(0.5(n+4))+(+1/10)=0

We get rid of parentheses

2n^2-(0.5(n+4))+1/10=0

We multiply all the terms by the denominator


2n^2*10-((0.5(n+4)))*10+1=0

Wy multiply elements

20n^2-((0.5(n+4)))*10+1=0

We move all terms containing n to the left, all other terms to the right

20n^2-((0.5(n+4)))*10=-1

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