(2/5)t+21=15

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Solution for (2/5)t+21=15 equation: 



(2/5)t+21=15

We move all terms to the left:

(2/5)t+21-(15)=0



Domain of the equation: 5)t!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

(+2/5)t+21-15=0

We add all the numbers together, and all the variables

(+2/5)t+6=0

We multiply parentheses

2t^2+6=0

a = 2; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·2·6
Δ = -48
Delta is less than zero, so there is no solution for the equation

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