(2/5)w-w=-(1/5)(3w+2)

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Solution for (2/5)w-w=-(1/5)(3w+2) equation: 



(2/5)w-w=-(1/5)(3w+2)

We move all terms to the left:

(2/5)w-w-(-(1/5)(3w+2))=0



Domain of the equation: 5)w!=0

w!=0/1

w!=0

w∈R





Domain of the equation: 5)(3w+2))!=0

w∈R



We add all the numbers together, and all the variables

(+2/5)w-w-(-(+1/5)(3w+2))=0

We add all the numbers together, and all the variables

-1w+(+2/5)w-(-(+1/5)(3w+2))=0

We multiply parentheses

2w^2-1w-(-(+1/5)(3w+2))=0

We multiply parentheses ..

2w^2-(-(+3w^2+1/5*2))-1w=0

We multiply all the terms by the denominator


3w^2+2w^2*5*2))-(-(-1w*5*2))+1=0

Wy multiply elements

3w^2+20w^3*2-10w^2*2=0

We do not support ewpression: w^3

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