(2/5)x+(1/5)x=360

Solution for (2/5)x+(1/5)x=360 equation:

(2/5)x+(1/5)x=360

We move all terms to the left:

(2/5)x+(1/5)x-(360)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/5)x+(+1/5)x-360=0

We multiply parentheses

2x^2+x^2-360=0

We add all the numbers together, and all the variables

3x^2-360=0

a = 3; b = 0; c = -360;
Δ = b2-4ac
Δ = 02-4·3·(-360)
Δ = 4320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4320}=\sqrt{144*30}=\sqrt{144}*\sqrt{30}=12\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{30}}{2*3}=\frac{0-12\sqrt{30}}{6}
=-\frac{12\sqrt{30}}{6}
=-2\sqrt{30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{30}}{2*3}=\frac{0+12\sqrt{30}}{6}
=\frac{12\sqrt{30}}{6}
=2\sqrt{30}
$