(2/5)x+(4/5)=-(4/5)

Solution for (2/5)x+(4/5)=-(4/5) equation:

(2/5)x+(4/5)=-(4/5)

We move all terms to the left:

(2/5)x+(4/5)-(-(4/5))=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/5)x+(+4/5)-(-(+4/5))=0

We multiply parentheses

2x^2+(+4/5)-(-(+4/5))=0

We get rid of parentheses

2x^2+4/5-(-(+4/5))=0

We calculate fractions


2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$