(2/5)x+2=-(3/5)x-5

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Solution for (2/5)x+2=-(3/5)x-5 equation:



(2/5)x+2=-(3/5)x-5
We move all terms to the left:
(2/5)x+2-(-(3/5)x-5)=0
Domain of the equation: 5)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 5)x-5)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+2/5)x-(-(+3/5)x-5)+2=0
We multiply parentheses
2x^2-(-(+3/5)x-5)+2=0
We multiply all the terms by the denominator
2x^2*5)x-5)-(-(+2*5)x-5)+3=0
We add all the numbers together, and all the variables
2x^2*5)x-5)-(-10x-5)+3=0
Wy multiply elements
10x^3=0
We do not support expression: x^3

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