(2/5)x+7/15=157/15,x=

Solution for (2/5)x+7/15=157/15,x= equation:

(2/5)x+7/15=157/15.x=

We move all terms to the left:

(2/5)x+7/15-(157/15.x)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 15.x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/5)x-(+157/15.x)+7/15=0

We multiply parentheses

2x^2-(+157/15.x)+7/15=0

We get rid of parentheses

2x^2-157/15.x+7/15=0

We calculate fractions


2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$