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(2/5)x-12=-20
We move all terms to the left:
(2/5)x-12-(-20)=0
Domain of the equation: 5)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/5)x-12-(-20)=0
We add all the numbers together, and all the variables
(+2/5)x+8=0
We multiply parentheses
2x^2+8=0
a = 2; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·2·8
Δ = -64
Delta is less than zero, so there is no solution for the equation
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