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(2/5)x-4=(7/5)x
We move all terms to the left:
(2/5)x-4-((7/5)x)=0
Domain of the equation: 5)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 5)x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/5)x-((+7/5)x)-4=0
We multiply parentheses
2x^2-((+7/5)x)-4=0
We multiply all the terms by the denominator
2x^2*5)x)-((-4*5)x)+7=0
We add all the numbers together, and all the variables
2x^2*5)x)-((-20)x)+7=0
Wy multiply elements
10x^3-20)x)+7=0
We do not support expression: x^3
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