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(2/5)x-7(1/5)x=11
We move all terms to the left:
(2/5)x-7(1/5)x-(11)=0
Domain of the equation: 5)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/5)x-7(+1/5)x-11=0
We multiply parentheses
2x^2-7x^2-11=0
We add all the numbers together, and all the variables
-5x^2-11=0
a = -5; b = 0; c = -11;
Δ = b2-4ac
Δ = 02-4·(-5)·(-11)
Δ = -220
Delta is less than zero, so there is no solution for the equation
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