(2/5)x-7=(12/2)x-2x+3

Solution for (2/5)x-7=(12/2)x-2x+3 equation:

(2/5)x-7=(12/2)x-2x+3

We move all terms to the left:

(2/5)x-7-((12/2)x-2x+3)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 2)x-2x+3)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/5)x-(6x-2x+3)-7=0

We multiply parentheses

2x^2-(6x-2x+3)-7=0

We get rid of parentheses

2x^2-6x+2x-3-7=0

We add all the numbers together, and all the variables

2x^2-4x-10=0

a = 2; b = -4; c = -10;
Δ = b2-4ac
Δ = -42-4·2·(-10)
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{6}}{2*2}=\frac{4-4\sqrt{6}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{6}}{2*2}=\frac{4+4\sqrt{6}}{4}
$