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(2/5)x=-10
We move all terms to the left:
(2/5)x-(-10)=0
Domain of the equation: 5)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/5)x-(-10)=0
We add all the numbers together, and all the variables
(+2/5)x+10=0
We multiply parentheses
2x^2+10=0
a = 2; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·2·10
Δ = -80
Delta is less than zero, so there is no solution for the equation
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