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(2/5)x=125/8
We move all terms to the left:
(2/5)x-(125/8)=0
Domain of the equation: 5)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/5)x-(+125/8)=0
We multiply parentheses
2x^2-(+125/8)=0
We get rid of parentheses
2x^2-125/8=0
We multiply all the terms by the denominator
2x^2*8-125=0
Wy multiply elements
16x^2-125=0
a = 16; b = 0; c = -125;
Δ = b2-4ac
Δ = 02-4·16·(-125)
Δ = 8000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8000}=\sqrt{1600*5}=\sqrt{1600}*\sqrt{5}=40\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{5}}{2*16}=\frac{0-40\sqrt{5}}{32} =-\frac{40\sqrt{5}}{32} =-\frac{5\sqrt{5}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{5}}{2*16}=\frac{0+40\sqrt{5}}{32} =\frac{40\sqrt{5}}{32} =\frac{5\sqrt{5}}{4} $
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