(2/5+4i)(3/7-2i)

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Solution for (2/5+4i)(3/7-2i) equation: 


i in (-oo:+oo)

(4*i+2/5)*(3/7-(2*i)) = 0

(4*i+2/5)*(3/7-2*i) = 0

( 3/7-2*i )

3/7-2*i = 0 // - 3/7

-2*i = -3/7 // : -2

i = -3/7/(-2)

i = 3/14

( 4*i+2/5 )

4*i+2/5 = 0 // - 2/5

4*i = -2/5 // : 4

i = -2/5/4

i = -1/10

i in { 3/14, -1/10 }

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