(2/5n)+((3n-4)/2n)=((n-2)/3n)

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Solution for (2/5n)+((3n-4)/2n)=((n-2)/3n) equation: 



(2/5n)+((3n-4)/2n)=((n-2)/3n)

We move all terms to the left:

(2/5n)+((3n-4)/2n)-(((n-2)/3n))=0



Domain of the equation: 5n)!=0

n!=0/1

n!=0

n∈R





Domain of the equation: 2n)!=0

n!=0/1

n!=0

n∈R





Domain of the equation: 3n))!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

(+2/5n)+((3n-4)/2n)-(((n-2)/3n))=0

We get rid of parentheses

2/5n+((3n-4)/2n)-(((n-2)/3n))=0

We calculate fractions

We do not support enpression: n^3

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