(2/5x)+(6/25x)=-16

Solution for (2/5x)+(6/25x)=-16 equation:

(2/5x)+(6/25x)=-16

We move all terms to the left:

(2/5x)+(6/25x)-(-16)=0


Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 25x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/5x)+(+6/25x)-(-16)=0

We add all the numbers together, and all the variables

(+2/5x)+(+6/25x)+16=0

We get rid of parentheses

2/5x+6/25x+16=0

We calculate fractions


50x/125x^2+30x/125x^2+16=0

We multiply all the terms by the denominator


50x+30x+16*125x^2=0

We add all the numbers together, and all the variables

80x+16*125x^2=0

Wy multiply elements

2000x^2+80x=0

a = 2000; b = 80; c = 0;
Δ = b2-4ac
Δ = 802-4·2000·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80}{2*2000}=\frac{-160}{4000}
=-1/25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80}{2*2000}=\frac{0}{4000}
=0
$