(2/5x)-(1/3x)=3

Solution for (2/5x)-(1/3x)=3 equation:

(2/5x)-(1/3x)=3

We move all terms to the left:

(2/5x)-(1/3x)-(3)=0


Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/5x)-(+1/3x)-3=0

We get rid of parentheses

2/5x-1/3x-3=0

We calculate fractions


6x/15x^2+(-5x)/15x^2-3=0

We multiply all the terms by the denominator


6x+(-5x)-3*15x^2=0

Wy multiply elements

-45x^2+6x+(-5x)=0

We get rid of parentheses

-45x^2+6x-5x=0

We add all the numbers together, and all the variables

-45x^2+x=0

a = -45; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-45)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-45}=\frac{-2}{-90}
=1/45
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-45}=\frac{0}{-90}
=0
$