(2/5x)=(-10/13)

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Solution for (2/5x)=(-10/13) equation: 



(2/5x)=(-10/13)

We move all terms to the left:

(2/5x)-((-10/13))=0



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/5x)-((-10/13))=0

We get rid of parentheses

2/5x-((-10/13))=0

We calculate fractions


()/65x^2+(-((-10*5x)/65x^2=0

We multiply all the terms by the denominator


(-((-10*5x)+()=0



We calculate terms in parentheses: +(-((-10*5x)+(), so:

-((-10*5x)+(





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-((-10*5x)+(





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-((-10*5x)+(





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-((-10*5x)+(





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-((-10*5x)+(





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-((-10*5x)+(





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-((-10*5x)+(





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-((-10*5x)+(





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-((-10*5x)+(





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-((-10*5x)+(





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