(2/7)(x+4)=-6

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Solution for (2/7)(x+4)=-6 equation: 



(2/7)(x+4)=-6

We move all terms to the left:

(2/7)(x+4)-(-6)=0



Domain of the equation: 7)(x+4)!=0

x∈R



We add all the numbers together, and all the variables

(+2/7)(x+4)-(-6)=0

We add all the numbers together, and all the variables

(+2/7)(x+4)+6=0

We multiply parentheses ..

(+2x^2+2/7*4)+6=0

We multiply all the terms by the denominator


(+2x^2+2+6*7*4)=0

We get rid of parentheses

2x^2+2+6*7*4=0

We add all the numbers together, and all the variables

2x^2+170=0

a = 2; b = 0; c = +170;
Δ = b2-4ac
Δ = 02-4·2·170
Δ = -1360
Delta is less than zero, so there is no solution for the equation

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