(2/7)*(5x-2)=18

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Solution for (2/7)*(5x-2)=18 equation:



(2/7)(5x-2)=18
We move all terms to the left:
(2/7)(5x-2)-(18)=0
Domain of the equation: 7)(5x-2)!=0
x∈R
We add all the numbers together, and all the variables
(+2/7)(5x-2)-18=0
We multiply parentheses ..
(+10x^2+2/7*-2)-18=0
We multiply all the terms by the denominator
(+10x^2+2-18*7*-2)=0
We get rid of parentheses
10x^2+2-2-18*7*=0
We add all the numbers together, and all the variables
10x^2=0
a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$

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