(2/7)*(5x-2)=8

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Solution for (2/7)*(5x-2)=8 equation: 



(2/7)(5x-2)=8

We move all terms to the left:

(2/7)(5x-2)-(8)=0



Domain of the equation: 7)(5x-2)!=0

x∈R



We add all the numbers together, and all the variables

(+2/7)(5x-2)-8=0

We multiply parentheses ..

(+10x^2+2/7*-2)-8=0

We multiply all the terms by the denominator


(+10x^2+2-8*7*-2)=0

We get rid of parentheses

10x^2+2-2-8*7*=0

We add all the numbers together, and all the variables

10x^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$

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