(2/7)j-(1/7)=(3/14+

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Solution for (2/7)j-(1/7)=(3/14+ equation: 



(2/7)j-(1/7)=(3/14+

We move all terms to the left:

(2/7)j-(1/7)-((3/14+)=0



Domain of the equation: 7)j!=0

j!=0/1

j!=0

j∈R



We add all the numbers together, and all the variables

(+2/7)j-(+1/7)-((+3/14)=0

We multiply parentheses

2j^2-(+1/7)-((+3/14)=0

We get rid of parentheses

2j^2-1/7-((+3/14)=0

We calculate fractions


2j^2+()/()+()/()=0

We add all the numbers together, and all the variables

2j^2+2=0

a = 2; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·2·2
Δ = -16
Delta is less than zero, so there is no solution for the equation

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