(2/7)x=-(10-x)

Solution for (2/7)x=-(10-x) equation:

(2/7)x=-(10-x)

We move all terms to the left:

(2/7)x-(-(10-x))=0


Domain of the equation: 7)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/7)x-(-(-1x+10))=0

We multiply parentheses

2x^2-(-(-1x+10))=0


We calculate terms in parentheses: -(-(-1x+10)), so:

-(-1x+10)

We get rid of parentheses

1x-10

We add all the numbers together, and all the variables

x-10

Back to the equation:

-(x-10)


We get rid of parentheses

2x^2-x+10=0

We add all the numbers together, and all the variables

2x^2-1x+10=0

a = 2; b = -1; c = +10;
Δ = b2-4ac
Δ = -12-4·2·10
Δ = -79
Delta is less than zero, so there is no solution for the equation