(2/9)z+7=1

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Solution for (2/9)z+7=1 equation: 



(2/9)z+7=1

We move all terms to the left:

(2/9)z+7-(1)=0



Domain of the equation: 9)z!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

(+2/9)z+7-1=0

We add all the numbers together, and all the variables

(+2/9)z+6=0

We multiply parentheses

2z^2+6=0

a = 2; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·2·6
Δ = -48
Delta is less than zero, so there is no solution for the equation

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