(2/9z)+7=1

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Solution for (2/9z)+7=1 equation: 



(2/9z)+7=1

We move all terms to the left:

(2/9z)+7-(1)=0



Domain of the equation: 9z)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

(+2/9z)+7-1=0

We add all the numbers together, and all the variables

(+2/9z)+6=0

We get rid of parentheses

2/9z+6=0

We multiply all the terms by the denominator


6*9z+2=0

Wy multiply elements

54z+2=0

We move all terms containing z to the left, all other terms to the right

54z=-2

z=-2/54

z=-1/27

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