(2/m)+17=(m/2)-7

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Solution for (2/m)+17=(m/2)-7 equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

2/m+17 = m/2-7 // - m/2-7

2/m-(m/2)+7+17 = 0

2*m^-1-1/2*m^1+24*m^0 = 0

(24*m^1-1/2*m^2+2*m^0)/(m^1) = 0 // * m^2

m^1*(24*m^1-1/2*m^2+2*m^0) = 0

m^1

(-1/2)*m^2+24*m+2 = 0

(-1/2)*m^2+24*m+2 = 0

DELTA = 24^2-(2*4*(-1/2))

DELTA = 580

DELTA > 0

m = (580^(1/2)-24)/(2*(-1/2)) or m = (-580^(1/2)-24)/(2*(-1/2))

m = 24-(2*145^(1/2)) or m = 24-(-2*145^(1/2))

m in { 24-(2*145^(1/2)), 24-(-2*145^(1/2))} 

m in { 24-(2*145^(1/2)), 24-(-2*145^(1/2)) }

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