(2/q-1)=(3/q-2)

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Solution for (2/q-1)=(3/q-2) equation: 



(2/q-1)=(3/q-2)

We move all terms to the left:

(2/q-1)-((3/q-2))=0



Domain of the equation: q-1)!=0

q∈R





Domain of the equation: q-2))!=0

q∈R



We get rid of parentheses

2/q-((3/q-2))-1=0

We calculate fractions


2q/q^2+(-((3*q)/q^2-1=0

We add all the numbers together, and all the variables

2q/q^2+(-((+3q)/q^2-1=0

We calculate fractions

We do not support eqpression: q^4

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