(2/u)+(1/6)=(5/6u)

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Solution for (2/u)+(1/6)=(5/6u) equation:


D( u )

u = 0

u = 0

u = 0

u in (-oo:0) U (0:+oo)

2/u+1/6 = (5/6)*u // - (5/6)*u

2/u-((5/6)*u)+1/6 = 0

(-5/6)*u+2/u+1/6 = 0

2*u^-1-5/6*u^1+1/6*u^0 = 0

(1/6*u^1-5/6*u^2+2*u^0)/(u^1) = 0 // * u^2

u^1*(1/6*u^1-5/6*u^2+2*u^0) = 0

u^1

(-5/6)*u^2+(1/6)*u+2 = 0

(-5/6)*u^2+(1/6)*u+2 = 0

DELTA = (1/6)^2-(2*4*(-5/6))

DELTA = 241/36

DELTA > 0

u = ((241/36)^(1/2)-(1/6))/(2*(-5/6)) or u = (-(1/6)-(241/36)^(1/2))/(2*(-5/6))

u = -3/5*((241/36)^(1/2)-1/6) or u = 3/5*((241/36)^(1/2)+1/6)

u in { -3/5*((241/36)^(1/2)-1/6), 3/5*((241/36)^(1/2)+1/6)}

u in { -3/5*((241/36)^(1/2)-1/6), 3/5*((241/36)^(1/2)+1/6) }

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