(2/x)+(3/x)=1/(x-4)

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Solution for (2/x)+(3/x)=1/(x-4) equation: 



(2/x)+(3/x)=1/(x-4)

We move all terms to the left:

(2/x)+(3/x)-(1/(x-4))=0



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: (x-4))!=0

x∈R



We add all the numbers together, and all the variables

(+2/x)+(+3/x)-(1/(x-4))=0

We get rid of parentheses

2/x+3/x-(1/(x-4))=0

We calculate fractions


-3x^2)+(-(1*x)/(-3x^2)+(3*(x-4))+2)/(=0



We calculate terms in parentheses: +(3*(x-4)), so:

3*(x-4)

We multiply parentheses

3x-12

Back to the equation:

+(3x-12)



We add all the numbers together, and all the variables

-3x^2)+(-(+x)/(-3x^2)+(3x-12)+2)/(=0

We get rid of parentheses

-3x^2)+(-(+x)/(-3x^2)+3x-12+2)/(=0

We calculate fractions


-3x^2)+(+(-(+x)*()/((-3x^2)*()+(-3x^2)+2)*()/((-3x^2)*()+3x-12=0

We can not solve this equation

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