(2/x)+3=(5/2x)+(13/4)

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Solution for (2/x)+3=(5/2x)+(13/4) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x+3 = (5/2)*x+13/4 // - (5/2)*x+13/4

2/x-((5/2)*x)-(13/4)+3 = 0

(-5/2)*x+2/x-13/4+3 = 0

2*x^-1-5/2*x^1-1/4*x^0 = 0

(2*x^0-5/2*x^2-1/4*x^1)/(x^1) = 0 // * x^2

x^1*(2*x^0-5/2*x^2-1/4*x^1) = 0

x^1

(-5/2)*x^2+(-1/4)*x+2 = 0

(-5/2)*x^2+(-1/4)*x+2 = 0

DELTA = (-1/4)^2-(2*4*(-5/2))

DELTA = 321/16

DELTA > 0

x = ((321/16)^(1/2)-(-1/4))/(2*(-5/2)) or x = (-(-1/4)-(321/16)^(1/2))/(2*(-5/2))

x = ((321/16)^(1/2)+1/4)/(-5) or x = (1/4-(321/16)^(1/2))/(-5)

x in { ((321/16)^(1/2)+1/4)/(-5), (1/4-(321/16)^(1/2))/(-5)}

x in { ((321/16)^(1/2)+1/4)/(-5), (1/4-(321/16)^(1/2))/(-5) }

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