(2/x)-(3/2)=(7/2x)

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Solution for (2/x)-(3/2)=(7/2x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x-(3/2) = (7/2)*x // - (7/2)*x

2/x-((7/2)*x)-(3/2) = 0

(-7/2)*x+2/x-3/2 = 0

2*x^-1-7/2*x^1-3/2*x^0 = 0

(2*x^0-7/2*x^2-3/2*x^1)/(x^1) = 0 // * x^2

x^1*(2*x^0-7/2*x^2-3/2*x^1) = 0

x^1

(-7/2)*x^2+(-3/2)*x+2 = 0

(-7/2)*x^2+(-3/2)*x+2 = 0

DELTA = (-3/2)^2-(2*4*(-7/2))

DELTA = 121/4

DELTA > 0

x = ((121/4)^(1/2)-(-3/2))/(2*(-7/2)) or x = (-(-3/2)-(121/4)^(1/2))/(2*(-7/2))

x = -1 or x = 4/7

x in { -1, 4/7} 

x in { -1, 4/7 }

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