(2/x+1)-(1/4)=(1/6x+6)

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Solution for (2/x+1)-(1/4)=(1/6x+6) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x-(1/4)+1 = (1/6)*x+6 // - (1/6)*x+6

2/x-((1/6)*x)-(1/4)-6+1 = 0

(-1/6)*x+2/x-1/4-6+1 = 0

2*x^-1-1/6*x^1-21/4*x^0 = 0

(2*x^0-1/6*x^2-21/4*x^1)/(x^1) = 0 // * x^2

x^1*(2*x^0-1/6*x^2-21/4*x^1) = 0

x^1

(-1/6)*x^2+(-21/4)*x+2 = 0

(-1/6)*x^2+(-21/4)*x+2 = 0

DELTA = (-21/4)^2-(2*4*(-1/6))

DELTA = 1387/48

DELTA > 0

x = ((1387/48)^(1/2)-(-21/4))/(2*(-1/6)) or x = (-(-21/4)-(1387/48)^(1/2))/(2*(-1/6))

x = -3*((1387/48)^(1/2)+21/4) or x = -3*(21/4-(1387/48)^(1/2))

x in { -3*((1387/48)^(1/2)+21/4), -3*(21/4-(1387/48)^(1/2))}

x in { -3*((1387/48)^(1/2)+21/4), -3*(21/4-(1387/48)^(1/2)) }

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