(2/x+2)+(3/x-4)=(18/(x+2)(x-4))

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Solution for (2/x+2)+(3/x-4)=(18/(x+2)(x-4)) equation: 



(2/x+2)+(3/x-4)=(18/(x+2)(x-4))

We move all terms to the left:

(2/x+2)+(3/x-4)-((18/(x+2)(x-4)))=0



Domain of the equation: x+2)!=0

x∈R





Domain of the equation: x-4)!=0

x∈R





Domain of the equation: (x+2)(x-4)))!=0

x∈R



We get rid of parentheses

2/x+3/x-((18/(x+2)(x-4)))+2-4=0

We multiply parentheses ..

-((18/(+x^2-4x+2x-8)))+2/x+3/x+2-4=0

We calculate fractions

We do not support expression: x^3

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