(2/x+3)-(1/x-3)=(4x/(x)(x)-9)

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Solution for (2/x+3)-(1/x-3)=(4x/(x)(x)-9) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x-(1/x)+3+3 = ((4*x)/x)*x-9 // - ((4*x)/x)*x-9

2/x-(((4*x)/x)*x)-(1/x)+3+3+9 = 0

2/x-4*x-x^-1+3+3+9 = 0

1*x^-1-4*x^1+15*x^0 = 0

(15*x^1-4*x^2+1*x^0)/(x^1) = 0 // * x^2

x^1*(15*x^1-4*x^2+1*x^0) = 0

x^1

15*x-4*x^2+1 = 0

15*x-4*x^2+1 = 0

DELTA = 15^2-(-4*1*4)

DELTA = 241

DELTA > 0

x = (241^(1/2)-15)/(-4*2) or x = (-241^(1/2)-15)/(-4*2)

x = (241^(1/2)-15)/(-8) or x = (241^(1/2)+15)/8

x in { (241^(1/2)-15)/(-8), (241^(1/2)+15)/8} 

x in { (241^(1/2)-15)/(-8), (241^(1/2)+15)/8 }

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