(2/x-3)+(1/x+2)=(3/x-2)

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Solution for (2/x-3)+(1/x+2)=(3/x-2) equation: 



(2/x-3)+(1/x+2)=(3/x-2)

We move all terms to the left:

(2/x-3)+(1/x+2)-((3/x-2))=0



Domain of the equation: x-3)!=0

x∈R





Domain of the equation: x+2)!=0

x∈R





Domain of the equation: x-2))!=0

x∈R



We get rid of parentheses

2/x+1/x-((3/x-2))-3+2=0

We calculate fractions


x/x^2+(-((3*x)/x^2-3+2=0

We add all the numbers together, and all the variables

x/x^2+(-((+3x)/x^2-3+2=0

We calculate fractions

We do not support expression: x^4

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