(2/x-3)+(3/4)=(17/2x)

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Solution for (2/x-3)+(3/4)=(17/2x) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x+3/4-3 = (17/2)*x // - (17/2)*x

2/x-((17/2)*x)+3/4-3 = 0

(-17/2)*x+2/x+3/4-3 = 0

2*x^-1-17/2*x^1-9/4*x^0 = 0

(2*x^0-17/2*x^2-9/4*x^1)/(x^1) = 0 // * x^2

x^1*(2*x^0-17/2*x^2-9/4*x^1) = 0

x^1

(-17/2)*x^2+(-9/4)*x+2 = 0

(-17/2)*x^2+(-9/4)*x+2 = 0

DELTA = (-9/4)^2-(2*4*(-17/2))

DELTA = 1169/16

DELTA > 0

x = ((1169/16)^(1/2)-(-9/4))/(2*(-17/2)) or x = (-(-9/4)-(1169/16)^(1/2))/(2*(-17/2))

x = ((1169/16)^(1/2)+9/4)/(-17) or x = (9/4-(1169/16)^(1/2))/(-17)

x in { ((1169/16)^(1/2)+9/4)/(-17), (9/4-(1169/16)^(1/2))/(-17)}

x in { ((1169/16)^(1/2)+9/4)/(-17), (9/4-(1169/16)^(1/2))/(-17) }

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