(2/x-3)=(-5/x+5)+(9/(x-3)(x+5))

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Solution for (2/x-3)=(-5/x+5)+(9/(x-3)(x+5)) equation:


D( x )

x = 0

x-3 = 0

x = 0

x = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:0) U (0:3) U (3:+oo)

2/x-3 = (9/(x-3))*(x+5)-5/x+5 // - (9/(x-3))*(x+5)-5/x+5

2/x-((9/(x-3))*(x+5))-(-5/x)-5-3 = 0

2/x-9*(x-3)^-1*(x+5)+5*x^-1-5-3 = 0

(-9*(x+5))/(x-3)+2/x+5/x-5-3 = 0

(-9*x*(x+5))/(x*(x-3))+(2*(x-3))/(x*(x-3))+(5*(x-3))/(x*(x-3))+(-5*x*(x-3))/(x*(x-3))+(-3*x*(x-3))/(x*(x-3)) = 0

2*(x-3)-9*x*(x+5)+5*(x-3)-5*x*(x-3)-3*x*(x-3) = 0

5*x-9*x^2-5*x^2-3*x^2-43*x+15*x+9*x-15-6 = 0

15*x-9*x^2-5*x^2-3*x^2-38*x+9*x-21 = 0

9*x-14*x^2-3*x^2-23*x-21 = 0

-17*x^2-14*x-21 = 0

-17*x^2-14*x-21 = 0

-1*(17*x^2+14*x+21) = 0

17*x^2+14*x+21 = 0

DELTA = 14^2-(4*17*21)

DELTA = -1232

DELTA < 0

-1 = 0

-1/(x*(x-3)) = 0

-1/(x*(x-3)) = 0 // * x*(x-3)

-1 = 0

x belongs to the empty set

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