(2/y)+(4/y)=3

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Solution for (2/y)+(4/y)=3 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

2/y+4/y = 3 // - 3

2/y+4/y-3 = 0

6*y^-1 = 3 // : 6

y^-1 = 1/2

-1 < 0

1/(y^1) = 1/2 // * y^1

1 = 1/2*y^1 // : 1/2

2 = y^1

y = 2

y = 2

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