(2/y)=(7/y)-(1/3)

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Solution for (2/y)=(7/y)-(1/3) equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

2/y = 7/y-(1/3) // - 7/y-(1/3)

2/y-(7/y)+1/3 = 0

2/y-7*y^-1+1/3 = 0

-5*y^-1 = -1/3 // : -5

y^-1 = 1/15

-1 < 0

1/(y^1) = 1/15 // * y^1

1 = 1/15*y^1 // : 1/15

15 = y^1

y = 15

y = 15

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