(2/z+1)-(1/4)=(3/z+1)

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Solution for (2/z+1)-(1/4)=(3/z+1) equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

2/z-(1/4)+1 = 3/z+1 // - 3/z+1

2/z-(3/z)-(1/4)-1+1 = 0

2/z-3*z^-1-1/4-1+1 = 0

-1*z^-1 = 1/4 // : -1

z^-1 = -1/4

-1 < 0

1/(z^1) = -1/4 // * z^1

1 = -1/4*z^1 // : -1/4

-4 = z^1

z = -4

z = -4

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