(20(1)+1x)+(20(2)+2x)=108

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Solution for (20(1)+1x)+(20(2)+2x)=108 equation: 



(20(1)+1x)+(20(2)+2x)=108

We move all terms to the left:

(20(1)+1x)+(20(2)+2x)-(108)=0

We add all the numbers together, and all the variables

(x+201)+(2x+202)-108=0

We get rid of parentheses

x+2x+201+202-108=0

We add all the numbers together, and all the variables

3x+295=0

We move all terms containing x to the left, all other terms to the right

3x=-295

x=-295/3

x=-98+1/3

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