(20(2x+2y)+7y+3z)=200

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Solution for (20(2x+2y)+7y+3z)=200 equation:


Simplifying
(20(2x + 2y) + 7y + 3z) = 200
((2x * 20 + 2y * 20) + 7y + 3z) = 200
((40x + 40y) + 7y + 3z) = 200

Combine like terms: 40y + 7y = 47y
(40x + 47y + 3z) = 200

Remove parenthesis around (40x + 47y + 3z)
40x + 47y + 3z = 200

Solving
40x + 47y + 3z = 200

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-47y' to each side of the equation.
40x + 47y + -47y + 3z = 200 + -47y

Combine like terms: 47y + -47y = 0
40x + 0 + 3z = 200 + -47y
40x + 3z = 200 + -47y

Add '-3z' to each side of the equation.
40x + 3z + -3z = 200 + -47y + -3z

Combine like terms: 3z + -3z = 0
40x + 0 = 200 + -47y + -3z
40x = 200 + -47y + -3z

Divide each side by '40'.
x = 5 + -1.175y + -0.075z

Simplifying
x = 5 + -1.175y + -0.075z

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