(20)(10)=0.05x+0.40(10-x)

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Solution for (20)(10)=0.05x+0.40(10-x) equation:



(20)(10)=0.05x+0.40(10-x)
We move all terms to the left:
(20)(10)-(0.05x+0.40(10-x))=0
We add all the numbers together, and all the variables
-(0.05x+0.40(-1x+10))+2010=0
We calculate terms in parentheses: -(0.05x+0.40(-1x+10)), so:
0.05x+0.40(-1x+10)
We multiply parentheses
0.05x-0.4x+4
We add all the numbers together, and all the variables
-0.35x+4
Back to the equation:
-(-0.35x+4)
We get rid of parentheses
0.35x-4+2010=0
We add all the numbers together, and all the variables
0.35x+2006=0
We move all terms containing x to the left, all other terms to the right
0.35x=-2006
x=-2006/0.35
x=-5731+0.15000000000009/0.35

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