(20)+(3x+20)=(4x+50)(10)

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Solution for (20)+(3x+20)=(4x+50)(10) equation: 



(20)+(3x+20)=(4x+50)(10)

We move all terms to the left:

(20)+(3x+20)-((4x+50)(10))=0

We get rid of parentheses

3x-((4x+50)10)+20+20=0



We calculate terms in parentheses: -((4x+50)10), so:

(4x+50)10

We multiply parentheses

40x+500

Back to the equation:

-(40x+500)



We add all the numbers together, and all the variables

3x-(40x+500)+40=0

We get rid of parentheses

3x-40x-500+40=0

We add all the numbers together, and all the variables

-37x-460=0

We move all terms containing x to the left, all other terms to the right

-37x=460

x=460/-37

x=-12+16/37

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