(20+2i)-(4-6i)-(-12+3i)=

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Solution for (20+2i)-(4-6i)-(-12+3i)= equation: 


Simplifying
(20 + 2i) + -1(4 + -6i) + -1(-12 + 3i) = 0

Remove parenthesis around (20 + 2i)
20 + 2i + -1(4 + -6i) + -1(-12 + 3i) = 0
20 + 2i + (4 * -1 + -6i * -1) + -1(-12 + 3i) = 0
20 + 2i + (-4 + 6i) + -1(-12 + 3i) = 0
20 + 2i + -4 + 6i + (-12 * -1 + 3i * -1) = 0
20 + 2i + -4 + 6i + (12 + -3i) = 0

Reorder the terms:
20 + -4 + 12 + 2i + 6i + -3i = 0

Combine like terms: 20 + -4 = 16
16 + 12 + 2i + 6i + -3i = 0

Combine like terms: 16 + 12 = 28
28 + 2i + 6i + -3i = 0

Combine like terms: 2i + 6i = 8i
28 + 8i + -3i = 0

Combine like terms: 8i + -3i = 5i
28 + 5i = 0

Solving
28 + 5i = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-28' to each side of the equation.
28 + -28 + 5i = 0 + -28

Combine like terms: 28 + -28 = 0
0 + 5i = 0 + -28
5i = 0 + -28

Combine like terms: 0 + -28 = -28
5i = -28

Divide each side by '5'.
i = -5.6

Simplifying
i = -5.6

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