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(20+2x)(15+2x)-20*15=456
We move all terms to the left:
(20+2x)(15+2x)-20*15-(456)=0
determiningTheFunctionDomain (20+2x)(15+2x)-456-20*15=0
We add all the numbers together, and all the variables
(2x+20)(2x+15)-456-20*15=0
We add all the numbers together, and all the variables
(2x+20)(2x+15)-756=0
We multiply parentheses ..
(+4x^2+30x+40x+300)-756=0
We get rid of parentheses
4x^2+30x+40x+300-756=0
We add all the numbers together, and all the variables
4x^2+70x-456=0
a = 4; b = 70; c = -456;
Δ = b2-4ac
Δ = 702-4·4·(-456)
Δ = 12196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12196}=\sqrt{4*3049}=\sqrt{4}*\sqrt{3049}=2\sqrt{3049}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-2\sqrt{3049}}{2*4}=\frac{-70-2\sqrt{3049}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+2\sqrt{3049}}{2*4}=\frac{-70+2\sqrt{3049}}{8} $
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