If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(20+2x)(15+2x)=600
We move all terms to the left:
(20+2x)(15+2x)-(600)=0
We add all the numbers together, and all the variables
(2x+20)(2x+15)-600=0
We multiply parentheses ..
(+4x^2+30x+40x+300)-600=0
We get rid of parentheses
4x^2+30x+40x+300-600=0
We add all the numbers together, and all the variables
4x^2+70x-300=0
a = 4; b = 70; c = -300;
Δ = b2-4ac
Δ = 702-4·4·(-300)
Δ = 9700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9700}=\sqrt{100*97}=\sqrt{100}*\sqrt{97}=10\sqrt{97}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-10\sqrt{97}}{2*4}=\frac{-70-10\sqrt{97}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+10\sqrt{97}}{2*4}=\frac{-70+10\sqrt{97}}{8} $
| -7-121=-3y-5 | | n÷5=11 | | 8x-7=-5x+9 | | F(x)=7x^2+3 | | (X)x.15=39 | | Xx.15=39 | | 6x+4=34+4 | | 5^(2*x)+1=(26*5^(x-1)) | | X+(3x-7)=49 | | -8=6f | | 7-2x^2-5x=4 | | 7m^2-17m+6=0 | | 3x+5=0.5x | | –y+7y=–24 | | (X+3)=(6x-3) | | 5x^2-8x^2=0 | | –r+15=2 | | x2–11x+8=0 | | m=-5;(-3,9) | | m=-5;(-6,0) | | 1/3x+3-4/3=-3-2x | | 4(2x+3)-4=4x+20 | | 3x-16=40=8 | | g/5=(700-2)/5 | | 3x-6=40=8 | | X⁴-6x³+7x²+6x-3=0 | | 3(x+3)=14+2x | | 3(4x+2)=20x9x+2 | | 277-3(x+8)=84 | | x-4÷5=2 | | (x+7)^(2)=9 | | 3(2p+6)+4(p+3)+6(5p-1)=10(p-3)+6(p-1 |