(20+2x)x(10+2x)=320

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Solution for (20+2x)x(10+2x)=320 equation:


Simplifying
(20 + 2x) * x(10 + 2x) = 320

Reorder the terms for easier multiplication:
x(20 + 2x)(10 + 2x) = 320

Multiply (20 + 2x) * (10 + 2x)
x(20(10 + 2x) + 2x * (10 + 2x)) = 320
x((10 * 20 + 2x * 20) + 2x * (10 + 2x)) = 320
x((200 + 40x) + 2x * (10 + 2x)) = 320
x(200 + 40x + (10 * 2x + 2x * 2x)) = 320
x(200 + 40x + (20x + 4x2)) = 320

Combine like terms: 40x + 20x = 60x
x(200 + 60x + 4x2) = 320
(200 * x + 60x * x + 4x2 * x) = 320
(200x + 60x2 + 4x3) = 320

Solving
200x + 60x2 + 4x3 = 320

Solving for variable 'x'.

Reorder the terms:
-320 + 200x + 60x2 + 4x3 = 320 + -320

Combine like terms: 320 + -320 = 0
-320 + 200x + 60x2 + 4x3 = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(-80 + 50x + 15x2 + x3) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(-80 + 50x + 15x2 + x3)' equal to zero and attempt to solve: Simplifying -80 + 50x + 15x2 + x3 = 0 Solving -80 + 50x + 15x2 + x3 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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