(20+x)(20+x)=(x+2)(46-x)

Solution for (20+x)(20+x)=(x+2)(46-x) equation:

(20+x)(20+x)=(x+2)(46-x)

We move all terms to the left:

(20+x)(20+x)-((x+2)(46-x))=0

We add all the numbers together, and all the variables

(x+20)(x+20)-((x+2)(-1x+46))=0

We multiply parentheses ..

(+x^2+20x+20x+400)-((x+2)(-1x+46))=0


We calculate terms in parentheses: -((x+2)(-1x+46)), so:

(x+2)(-1x+46)

We multiply parentheses ..

(-1x^2+46x-2x+92)

We get rid of parentheses

-1x^2+46x-2x+92

We add all the numbers together, and all the variables

-1x^2+44x+92

Back to the equation:

-(-1x^2+44x+92)


We get rid of parentheses

x^2+1x^2+20x+20x-44x+400-92=0

We add all the numbers together, and all the variables

2x^2-4x+308=0

a = 2; b = -4; c = +308;
Δ = b2-4ac
Δ = -42-4·2·308
Δ = -2448
Delta is less than zero, so there is no solution for the equation